((1^2-a^2)/(a^2-1))+1

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Solution for ((1^2-a^2)/(a^2-1))+1 equation: 


D( a )

a^2-1 = 0

a^2-1 = 0

a^2-1 = 0

1*a^2 = 1 // : 1

a^2 = 1

a^2 = 1 // ^ 1/2

abs(a) = 1

a = 1 or a = -1

a in (-oo:-1) U (-1:1) U (1:+oo)

(1^2-a^2)/(a^2-1)+1 = 0

(1-a^2)/(a^2-1)+1 = 0

(1-a^2)/(a^2-1)+(1*(a^2-1))/(a^2-1) = 0

1*(a^2-1)-a^2+1 = 0

0 = 0

0/(a^2-1) = 0

0/(a^2-1) = 0 // * a^2-1

0 = 0

a belongs to the empty set

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